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Vladimir79 [104]

2 years ago

8

Quadrilateral EFGH is inscribed inside a circle as shown below. Write a proof showing that angles H and F are supplementary. Cir

cle J is shown with an inscribed quadrilateral labeled EFGH.
NO LINKS OR ABSURD ANSWERS

1 answer:

vladimir1956 [14]2 years ago

7 0

Answer:

That is called a cyclic quadrilateral. Angles E and G add up to 180 degrees and angles H and F add up to 180 degrees.

Supplementary angles are two angles whose measures add up to 180°

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Given 16 = −5 + z4solve for z

AysviL [449]

Hi,

$16 = - 5 + z4 \\ - 4z + 16 = - 5 \\ - 4z = - 5 - 16 \\ - 4z = -21$

Now just divide both sides of equation by -4.

$z = \frac{21}{4}$

Simplify:

$z = 5 \frac{1}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: fraction \: result$

Decimal form:

$z = 5.25 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: decimal \: result$

Hope this helps.
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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Find the measure of arc AC whose inscribed angle is 62 degrees.

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3 0

2 years ago

Paul has $78 in the bank and saves $30 each week. What is the initial value? Be sure to use negative signs if needed.

marin [14]

Answer:

The initial value is $78

Step-by-step explanation:

Given

$Base\ Amount = \$78$

$Additional = \$30$ (weekly)

Required

Determine the initial value

The initial value is the amount he has in its bank account before making his weekly savings.

From the question, we have that his initial balance is $78.

Hence, the initial value is $78

However, his weekly balance can be expressed as:

$Balance = Base\ Amount + Additional * number\ of weeks$

Represent number of weeks with x; So, we have:

$Balance = 78 + 30 * x$

$Balance = 78 + 30 x$

6 0

2 years ago

PLSSS ANSWER, 35 pointss

xxTIMURxx [149]

Answer:

1.

$(y - 5)(x + y)$

2.

${(x - y)}(x - y + a)$

3.

$(b - 3)(5b - 17)$

Step-by-step explanation:

1. The given polynomial is

$x(y - 5) - y(5 - y)$

We need to factor the second part to get:

$x(y - 5) + y(y - 5)$

We factor y-5 to obtain:

$(y - 5)(x + y)$

2. We have

${(x - y)}^{2} - a(y - x)$

We again factor -1 from the second part to get:

${(x - y)}^{2} + a(x- y)$

We now factor x-y to get:

${(x - y)}^{2} + a(x- y)$

${(x - y)}(x - y + a)$

3. We have

$2(3 - b) + 5 {(b - 3})^{2}$

We factor negative 1 from the first part to get

$- 2(b - 3) + 5 {(b - 3})^{2}$

We now factor b-3 to get:

$(b - 3)( - 2 + 5(b - 3))$

We now simplify to get:

$(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)$

4 0

2 years ago