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sergejj [24]
3 years ago
7

What is the solution to (x – 3)3(x + 1)(x – 2) ≤ 0?

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

B

.....................

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I have checked and the answer is x=7
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Patricia is studying a polynomial function f(x). Three given roots of f(x) are -11-square root 2i, 3 + 4i, and 10. Patricia conc
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In order for the polynomial to be a degree of 4, it must have exactly 4 roots. According to the fundamental theorem of algebra: "The number of roots in a function is equivalent to the degree of the function"

These roots do not have to be real numbers, which means they can be imaginary or complex.

In this case, (-11 - √2i), (3 + 4i), and 10. There are three roots, which means that the polynomial can be a third of fourth degree polynomial. It is wrong for Patricia to assume that this is a fourth degree polynomial when only three roots are known.

<h3><u>The degree of the polynomial will at least be three, but could be higher.</u></h3>
4 0
4 years ago
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The numerator of a fraction (which is in its simplest form) is 5 less than the denominator. If the numerator is multiplied by 2,
timama [110]
N = d - 5

2n/(d + 16) = n/d - 1/3 n/d
2n/(d + 16) = 2/3 n/d Divide by 2n
1 / (d + 16) = 1/3 d
Here's the tricky part.
d + 16 = 3d the two denominators are equal. the numerators are both 1.
16 = 2d
d = 8
so the numerator is d - 5
n = 8 - 5
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Let's see if it checks out.
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2*3 = 6
8 + 16 = 24
New fraction 6/24 = 1/4
(3/8 - 1/3 ) = 1/8
3/8 - 1/8 = 1/4 so it checks with the original conditions put on it.


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3 years ago
If the test scores of a class of 36 students have a mean of 75.2 and the test scores of another class of 28 students have a mean
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The mean of the combined group is 71.3 --- hope this helps
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4 years ago
**PLEASE HELP ASAP** Terri is analyzing a circle, y^2 + x^2 = 36, and a linear function g(x). Will they intersect?
Alborosie
We analyze the linear function to find that it has equation y=x.  Drawing the line, we find that it will intersect the circle at negative and positive x-coordinates.

We can prove this by substituting y=x into the given equation:

x^2+x^2=36

2x^2=36

x^2 = 18

x = \pm 3\sqrt{2}

Hence, x = 3\sqrt{2} or -\sqrt{2}, so there are both positive and negative values for x.
5 0
3 years ago
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