<u>Answer</u>
≈ 11.1803398874989485
<u>Detailed Explanation </u>
We will be using the distance formula for this problem

Now, let's input the numbers into the formula.

Solve.
Therefore, the distance between the two points is
≈ 11.1803398874989485
I would say a cause they have the same curves
Answer:

Step-by-step explanation:
The combined distance that both planes will cover is 200 miles
Time taken by both planes will be the same (t)

So, the combined distance is

They will meet in
.
<span>x + (x + 1)
.............
</span>
Thirty three thousand and ninety one