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Rina8888 [55]
2 years ago
8

How to solve the equation l=2x-3

Mathematics
1 answer:
Elden [556K]2 years ago
6 0

Answer:

I-2x=-3

Step-by-step explanation:

Yiu can only simplify this equatuon

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What does an r value of −1 represent in correlation?
BARSIC [14]
It means the scatter plot is a line with negative slope. The relation is perfectly described by a linear equation.
4 0
2 years ago
11. Maria's age is 3 years more than twice George's age. Which expression represents George's age in terms of Maria's?
leonid [27]

Answer:

C

Step-by-step explanation:

Okay, the catch of this question is that they do a very good job of explaining Maria's age in terms of George's age, but they leave George's age in terms of Maria's all up to you.

First start off by doing an expression of what they explicitly give you. Maria's age in terms of George's age.

Let's use variables g, representing George's age and m representing Maria's age

m = 2g + 3

Okay, this is all dandy and all, but they ask us for George's age in terms of Maria's, so we need to isolate for g.

subtract the 3 from both sides, like so:

m - 3 = 2g

then divide 2 from both sides: (remember we're dividing the whole thing)

(m-3)/2 = g

Now we have an expression for George's age in terms of Maria's.

g = (m-3)/2 or g = \frac{m-3}{2}

The answer that gives us this, is C.

6 0
2 years ago
A hyena runs 2 kilometers for every 25 kilometer a mouse runs. Select from the drop-down menu to correctly complete the statemen
NARA [144]

Answer:

make a chart to see the difference between the two animals

5 0
2 years ago
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Determine determine whether the following geometric series converges or diverges. if the series converges find its sum.
Lilit [14]

For starters,

\dfrac{3^k}{4^{k+2}}=\dfrac{3^k}{4^24^k}=\dfrac1{16}\left(\dfrac34\right)^k

Consider the nth partial sum, denoted by S_n:

S_n=\dfrac1{16}\left(\dfrac34\right)+\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\cdots+\dfrac1{16}\left(\dfrac34\right)^n

Multiply both sides by \frac34:

\dfrac34S_n=\dfrac1{16}\left(\dfrac34\right)^2+\dfrac1{16}\left(\dfrac34\right)^3+\dfrac1{16}\left(\dfrac34\right)^4+\cdots+\dfrac1{16}\left(\dfrac34\right)^{n+1}

Subtract S_n from this:

\dfrac34S_n-S_n=\dfrac1{16}\left(\dfrac34\right)^{n+1}-\dfrac1{16}\left(\dfrac34\right)

Solve for S_n:

-\dfrac14S_n=\dfrac3{64}\left(\left(\dfrac34\right)^n-1\right)

S_n=\dfrac3{16}\left(1-\left(\dfrac34\right)^n\right)

Now as n\to\infty, the exponential term will converge to 0, since r^n\to0 if 0. This leaves us with

\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{k=1}^n\frac{3^k}{4^{k+2}}=\sum_{k=1}^\infty\frac{3^k}{4^{k+2}}=\frac3{16}

8 0
3 years ago
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Sin θ > 0 and tan θ < 0 then:
andriy [413]

Answer:

last choice

Step-by-step explanation:

sin(theta) is positive

tan(theta)=sin(theta)/cos(theta) is negative

If sin(theta) is positive and tan(theta) is negative, then cos(theta) is negative because +/-=-

So we are looking for the quadrant where sine is positive and cosine is negative or when x is negative and y is positive.

This is in quadrant 2 so our angle theta is between 90 and 180 degrees.

4 0
2 years ago
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