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3 years ago

Factor completely 36x^2-25

Mathematics

1 answer:

miss Akunina [59]3 years ago

7 0

Factor completely 36x^2-25

Answer:

<h2>a^2−b^2=(a+b)(a−b)</h2><h2>where </h2><h2>a=6x</h2><h2>and </h2><h2>b=5</h2><h2>(6x+5)(6x−5)</h2>

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there arre 221 students on a fiel trip five students ride in a van the rest of the students fill the 6 buses enter an equation t

iren2701 [21]

According to the question statement, the total sum of students is 221, which includes the students that ride on bus and the students that ride in a van.

The students that ride in a van are five, the students that ride on bus are 6 times s which is the product of the number of buses and the number of students that are on each bus.

Write all this information into an equation, this way:

$6s+5=221$

Now, solve the equation for s to find the number of students that are on each bus.

$\begin{gathered} 6s+5=221 \\ 6s=216 \\ s=\frac{216}{6} \\ s=36 \end{gathered}$

There are 36 students on each bus.

3 0

1 year ago

The rule that applies to the following number sentence 0÷7=0

Maurinko [17]

Anything multiplied by zero is zero

6 0

3 years ago

Read 2 more answers

Let n be a natural number. Show that 3 | n3 −n

Vladimir [108]

Let $n=1$ . Then $n^3-n=1^3-1=0$ . By convention, every non-zero integer $n$ divides 0, so $3\vert n^3-n$ .

Suppose this relation holds for $n=k$ , i.e. $3\vert k^3-k$ . We then hope to show it must also hold for $n=k+1$ .

You have

$(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)$

We assumed that $3\vert k^3-k$ , and it's clear that $3\vert 3(k^2+k)$ because $3(k^2+k)$ is a multiple of 3. This means the remainder upon divides $(k+1)^3-(k+1)$ must be 0, and therefore the relation holds for $n=k+1$ . This proves the statement.

4 0

3 years ago

Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long

7nadin3 [17]

The first thing we must do for this case is find the scale factor.
We have then that for the larger side of both triangle, the scale factor is:
$k = \frac{RP}{HF}$
$k = \frac{7.2}{12}$
$k = 0.6$
To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
We have then:

For PQ
$PQ = k * FG

PQ = 0.6 * 5

PQ = 3$

For QR
$QR = k * GH

QR = 0.6 * 10

QR = 6$

Answer:
You have that the lengths for the other two sides of triangle PQR are:
$PQ = 3

QR = 6$

3 0

3 years ago

IM BEGGING PLEASE HELP One angle of the triangle is 30% larger than the other and 36 ° smaller than the third. Find the angles o

Zigmanuir [339]

9514 1404 393

Answer:

52°, 40°, 88°

Step-by-step explanation:

Let x represent "one angle". This is 30% larger than "the other", so we have ...

x = "the other" × (1 +30%)

x/1.30 = "the other"

If x is 36° smaller than the third, then the third is x+36.

The sum of the angles is 180°.

x + x/1.3 + (x +36) = 180

x(2 +1/1.3) = 144

x = 144/(2 +1/1.3) = 52

x/1.3 = 52/1.3 = 40

x +36 = 88

The angles of the triangle are 52°, 40°, and 88°.

7 0

3 years ago