if ∠C = 104 + ∠B = 31, therefore ∠A = 45 (A + B + C = 180)
Sin45 / 3 5/8 = Sin31 / b (multiply both sides by b) bSin45 / 3 5/8 = Sin31 (multiply both sides by 3 5/8) bSin45 = 3 5/8Sin31 (divide by Sin45) b = 3.625Sin31 / sin45 b = 2.64
Sin45 / 3 5/8 = Sin104 / c (multiply by c) cSin45 / 3 5/8 = Sin104 (multiply both sides by 3 5/8) cSin45 = 3 5/8Sin104 (divide by Sin45) c = 3.62Sin104 / Sin45 c = 4.97