Answer:
f(g(x)) = 722, and g(f(x)) = 154
Step-by-step explanation:
f(x) = 2x²
g(x) = 3x + 4
g(f(x)) = 3(2x²) + 4
g(f(5)) = 3(2 × 5²) + 4
g(f(5)) = 3(2 × 25) + 4
g(f(5)) = 3 × 50 + 4
g(f(5)) = 154
f(g(x)) = 2(3x + 4)²
f(g(5)) = 2(3 × 5 + 4)²
f(g(5)) = 2 × 19²
f(g(5)) = 2 × 361
f(g(5)) = 722
Answer:
The average number of points this player will get in 100 one-and-one free throw situations is 70.
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either the player makes it, or he does not. The probability of the player making a free throw is independent of other free throws. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

70% free throw percentage.
This means that 
What is the average number of points this player will get in 100 one-and-one free throw situations?
This is E(X) when n = 100. So

The average number of points this player will get in 100 one-and-one free throw situations is 70.
Answer:
y2-y1/x2-x1
Step-by-step explanation:
x1= -4 x2= -5
y1= 8 y2= -6
-6-8/-5+4=14
so M = 14
y-y1=m(x-x1)
y-8=14(x+4)
8y=14x+56
rearrange
-14x+8y=56
but you need it in the form of AX+BX=C (THE X SHOULD BE POSITIVE SO CHNAGE ALL THE SIGNS )
14X-8Y=-56
If Alan knows one already, there is 3 more left for him to possibly know
Answer:
Step-by-step explanation:
10h+15=65 subtract 15 from each side
10h=50, divide each side by 10
h=5
He was at the fair for 5 hours