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Burka [1]
3 years ago
11

Plot (−2 3/4, −4 1/2) on the coordinate plane.

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0
Because -2 3/4 is on the x axis, it is the diagonal one, -4 1/2 is on the y axis it’s vertical.

The first number is x, the second is y.

Brainliest answer please?

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Bruh on jah i cant figure thes out help plz
Leokris [45]
5 1/3

8 2/15
2 4/5 change to 2 12/15

8 2/15 change to 7 17/15
-2 12/15


7 17/15
-2 12/15
——-——
5 5/15 reduced to 5 1/3

CAN EXPLAIN FURTHER

4 0
2 years ago
Read 2 more answers
Please solve both step by step I'll mark you as brainliest
Kitty [74]

Answer:

5. -5x - 1

6. -x - 4

Step-by-step explanation:

5.

Distribute (get rid of parentheses):

-5x - 1

6.

Distribute (get rid of parentheses):

-x - 4

6 0
3 years ago
Read 2 more answers
gina pasted 3 stickers in a book. if she added one sticker to her collection every day, what equation represents the relationshi
lukranit [14]

Answer:

The answer to your question is

                       Number of stickers = number of days + 3

Step-by-step explanation:

- To find the equation of the line that represents the situation, first, find the slope.

Slope = m = \frac{y2 - y1}{x2 - x1}

             m = \frac{4 - 3}{1 - 0} = \frac{1}{1} = 1

- Find the equation of the line

                      y - y1 = m(x - x1)

                      y - 4 = 1(x - 1)

                      y - 4 = x - 1

                           y = x - 1 + 4

                           y = x + 3

y = number of stickers

x = days

                     Number of stickers = number of days + 3

3 0
3 years ago
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°
djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, \angle ABN is 37°. We can see from the diagram that \angle ABC would be 180-37= 143°.

Also, the new bearing is N 25°E. So, \angle BCA would be 25°.

Now we can find \angle BAC. As the sum of the internal angle of a triangle is 180°.

\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is AC=x

We can apply the sine rule now.

\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0
3 years ago
I need help on this homework
wel
(-9x²-2x) - (-9x²-3x) = (-9x²-2x) +(9x²+3x) = -9x²-2x+9x²+3x = (-9x²+9x²)+(-2x+3x) = x
8 0
3 years ago
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