Answer:
Suppose N is the size of a population of radioactive atoms at a given time t, and dN is the amount by which the population decreases in time dt; then the rate of change is given by the equation dN/dt = −λN, where λ is the decay constant.
Answer:
y=-5/7(x+4)+7
Step-by-step explanation:
![\frac{9(14+16)*2-(8*4+12*9)}{40} \\ \frac{(9*2)(14+16)-[(8*4)+(12*9)]}{40}\\ \frac{(18*30)-(32+108)}{40}\\ \frac{540-140}{40}\\ \frac{400}{40}\\ 10](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%2814%2B16%29%2A2-%288%2A4%2B12%2A9%29%7D%7B40%7D%20%5C%5C%0A%5Cfrac%7B%289%2A2%29%2814%2B16%29-%5B%288%2A4%29%2B%2812%2A9%29%5D%7D%7B40%7D%5C%5C%0A%5Cfrac%7B%2818%2A30%29-%2832%2B108%29%7D%7B40%7D%5C%5C%0A%5Cfrac%7B540-140%7D%7B40%7D%5C%5C%0A%5Cfrac%7B400%7D%7B40%7D%5C%5C%0A10)
So the expression is equal to
10.
Answer:the weight after 225 days is
22885 kilograms
Step-by-step explanation:
The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.
The formula for the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
n is the number of terms of the sequence.
a is the first term
d is the common difference
We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225
Therefore
T225 = 2725 + (225 - 1)90
T225 = 2725 + 224×90 = 2725 + 20160
T225 = 22885
