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Bumek [7]
3 years ago
10

Graph the linear equation in three plots: -x+2y=11

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

Convert the given equation to the form y = mx + b:

-x+2y=11          <em>add x to both sides</em>

2y=x+11          <em>divide both sides by 2</em>

y=\dfrac{1}{2}x+\dfrac{11}{2}

It's a linear function.

We need only two points to plot the graph. Select any two x values, insert into the equation and calculate y values.

for x = 1

y=\dfrac{1}{2}(1)+\dfrac{11}{2}=\dfrac{1}{2}+\dfrac{11}{2}=\dfrac{12}{2}=6\to(1,\ 6)

for x = -5

y=\dfrac{1}{2}(-5)+\dfrac{11}{2}=-\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{6}{2}=3\to(-5,\ 3)

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Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

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\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

Hope this helps!
5 0
3 years ago
Subtract: (x2 − 8x + 5) − (−3x2 + 5x − 9) help me please.
kicyunya [14]
The answer is 4x^2-13x+14
8 0
3 years ago
Suppose you are given a parabola with two points that have the same y-value, such as (-7, 11) and (3, 11). Explain how to find t
Hoochie [10]

By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.

<h3>How to derive the equation of the axis of symmetry </h3>

In this question we know the locations of two points with the same y-value, which means that the axis of symmetry is parallel to the y-axis and that both points are equidistant. Thus, the axis of symmetry passes through the midpoint of the line segment whose ends are those points.

First, calculate the coordinates of the midpoint by the midpoint formula:

M(x, y) = 0.5 · (- 7, 11) + 0.5 · (3, 11)

M(x, y) = (- 2, 11)

Second, look for the first coordinate of the midpoint and derive the equation of the line associated with the axis of symmetry:

x = - 2

By using the midpoint formula and the equation of the line, the equation of the line of symmetry is x = - 2.

To learn more on axes of symmetry: brainly.com/question/11957987

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3 0
1 year ago
I need help assap
Bad White [126]
It’s 2=x because you have start with 2 then 5
5 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

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6 0
1 year ago
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