We can use the subtraction method to solve this:
3x - 5 ≥ 4
x + 1 ≥ 2
2x - 6 ≥ 2
2x ≥ 8
The solution set is x ≥ 4
Answer:
(2.3, 4.1)
Step-by-step explanation:
I don't exactly know what you want answer wise
Step-by-step explanation:
-4j+ -1 + -4j+6
(-4j+-4j) + (-1+6)
-8j + 5 is the answer
Answer:
a = 2, b = - 3, c = - 8
Step-by-step explanation:
Expand f(x) = a(x + b)² + c and compare coefficients of like terms, that is
a(x + b)² + c ← expand (x + b)² using FOIL
= a(x² + 2bx + b²) + c ← distribute parenthesis by a
= ax² + 2abx + ab² + c
Compare like terms with f(x) = 2x² - 12x + 10
Compare coefficients x² term
a = 2
Compare coefficients of x- term
2ab = - 12, substitute a = 2
2(2)b = - 12
4b = - 12 ( divide both sides by 4 )
b = - 3
Compare constant term
ab² + c = 10 , substitute a = 2, b = - 3
2(- 3)² + c = 10
18 + c = 10 ( subtract 18 from both sides )
c = - 8
Then a = 2, b = - 3, c = - 8
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