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Sonja [21]
3 years ago
9

What is the value of x in the equation shown below x^3+1=9

Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

x^3 + 1 = 9

x^3 = 8

\sqrt[3]{x^3} = \sqrt[3]{8}

x = 2

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What is 1/6 divided by 1/3 in simplest form
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Answer:

1/2 or 0.5

Step-by-step explanation:

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In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
What is the equation of a line that passes through (4, 7) and has a slope of −14?
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Slope = -1/4
(4, 7)

y - 7 = -1/4 (x - 4)
y - 7 = -1/4x + 1
y = -1/4 + 8

answer is C
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3 years ago
A passenger train has tickets available for 12 window seats and 8 aisle seats. The nest person to buy a ticket will be randomly
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The probability of the person be set to sit in an aisle seat is 8/12.
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John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho
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The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as ^4C_1.

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

=\ ^2C_1 \times ^4C_1\\\\=\ 8

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

8 0
2 years ago
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