Answer:
Area : 114.25 in^2
Perimeter : 47.7 in
Step-by-step explanation:
In this problem when finding the perimeter you have a normal triangle and a semi-circle. so you add the 2 sides of the triangle and find the circumference of a semi-circle with a radius of 5.
17 + 15 + {(3.14)[2(5)]}/2 =
32 + {(3.14)[10]}/2 =
32 + 31.4/2 =
32 + 15.7 =
47.7
When finding the are you have to make the shapes as easy as possible. In this case you divide it to be triangle and semi-circle. Then add the 2 areas together.
[15(10)]/2 + {(3.14)[(5)^2]}/2
150/2 + {(3.14)[25]}/2
75 + 78.5/2
75 + 39.25
114.25
Answer: Length = 11
Width = 9
Step-by-step explanation:
Let x represent the unknown length.
Let x - 2 represent the unknown width.
The perimeter is equal to 2 times x + (x -2)
Equation:
2 (x + (x - 2)) = 40
x + (x - 2) = 40/2
x + x - 2 = 20
2x - 2 = 20
2x -2 + 2 = 20 + 2
The length is: 2x = 22 -> x = 22/2 -> x = 11
The width is: x - 2 = 9
Answer:
27Pi units squared
Step-by-step explanation:
step 1
Find the area of complete circle L
The area of circle is given by
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
we have
![r=KL=ML=9\ units](https://tex.z-dn.net/?f=r%3DKL%3DML%3D9%5C%20units)
substitute
![A=\pi (9)^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%289%29%5E%7B2%7D)
![A=81\pi\ units^2](https://tex.z-dn.net/?f=A%3D81%5Cpi%5C%20units%5E2)
step 2
Find the area of the shaded sector
we know that
The area of complete circle subtends a central angle of 360 degrees
so
using proportion
Find out the area of sector by a central angle of 120 degrees
![\frac{81\pi}{360^o}=\frac{x}{120^o}\\\\x=81\pi(120)/360\\\\x=27\pi\ units^2](https://tex.z-dn.net/?f=%5Cfrac%7B81%5Cpi%7D%7B360%5Eo%7D%3D%5Cfrac%7Bx%7D%7B120%5Eo%7D%5C%5C%5C%5Cx%3D81%5Cpi%28120%29%2F360%5C%5C%5C%5Cx%3D27%5Cpi%5C%20units%5E2)
75.2 is already rounded to the nearest tenth, if you meant tens it's 80