Answer:
3.54 and 1.04
Step-by-step explanation:
Given:
Two towns are 1,100 miles apart.
A group of hikers Starts from each town and walks down the trail toward each other..
They meet after a total hiking time of 240 hours.
If one group travels 2 1/2 mile per hour slower than the other group.
<u>Question asked:</u>
Find the rate of each group.
<u>Solution:</u>
Let speed of faster hiker = 
Speed of slower hiker = 
<u>As we know:</u>
<u />
Total distance between two town = Total combined speed of both hikers 
Total combined time taken
Speed of faster hiker = = 3.54 miles per hour.
Speed of slower hiker = =
Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.
<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
53800
- 52000
-------------
1800
Idk but you can get the answer from somebody else
