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pychu [463]
3 years ago
5

hELP!!! PLEASE?! BRAINLIEST ANSWER INCLUDED!!! A cashier has a total of 98 bills, made up of fives and fifties. The total value

of the money is $2425. How much of each kind does he have?
Mathematics
1 answer:
bulgar [2K]3 years ago
3 0
You would need 48 fifty dollar bills to make up 2,400 and you would need 5 five dollar bills to make up the 25, so then you’d have your answer which is $2,425.
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Which property will Sarah use to solve 6x = 42?
Katarina [22]

Answer:

7

Step-by-step explanation:

4 0
3 years ago
Write the equation of the line in slope intercept form if its slope is 3 and y intercept is -5
Veseljchak [2.6K]

Answer:

y = 3x - 5

Step-by-step explanation:

1. The slope-intercept form a line is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.

2. Given the values of m and b, let's plug them in:

  • y = (3)x+(-5)
  • y = 3x-5

Therefore, the equation of the line in slope-intercept form is y = 3x - 5.

Have a lovely rest of your day/night.

7 0
3 years ago
Read 2 more answers
How do yo solve (x-5)(-3)=18
tiny-mole [99]

Answer:

x = -1

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Given

(x - 5)(-3) = 18

Expand the bracket

x X -3 -5 x -3 = 18

-3x + 15 = 18

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-3x + 15 - 15 = 18 - 15

-3x = 3

Divide both sides by -3

-3x/-3 = 3/-3

x = -1

3 0
3 years ago
Find the total area of the regular pyramid
Evgesh-ka [11]

Answer:

Step-by-step explanation:

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3 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
Luda [366]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n



now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605


Hence answer is approx 1606 beetles will be there after 10 years.


To find answer for 20 years plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549


Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(1000\right)}{\log\left(1.32\right)}=n24.8810001465=n


Hence answer is approx 25 years.

8 0
3 years ago
Read 2 more answers
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