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irga5000 [103]
3 years ago
5

Given two people earning $10/hour, one person earning $15/hour, and two people earning $20/hour, what is the median pay rate bei

ng earned per hour for these five people?
Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
I think it would be $15/hour
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Verdich [7]

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A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length

Step-by-step explanation:

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3 years ago
The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

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3 years ago
Sandy and Alex are married, with no dependents. They wish to file a joint tax return. Both of them work, but their combined sala
GREYUIT [131]

Answer:I'm pretty sure it would be C but that might be wrong

Step-by-step explanation:

7 0
3 years ago
This too!!<br><br><br><br><br> . <br> Please<br><br><br><br><br> .
REY [17]

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In order to tell if these are congruent triangles we would need to know if angles Y and V were congruent, angles X and W are congruent or if segments XU and WU were congruent.

Step-by-step explanation:

Any of these would work because you can use two different methods to telling that these are congruent triangles.

The first method is called side-angle-side. In it you need two side lengths that are congruent with a congruent angle in the middle. Since we already know that the right angle in the middle is congruent, and we know YU and VU are congruent, we would just need to know the additional side to prove congruence.

The second method is called angle, angle side. In this we need to know that two angles in a row are congruent followed by a side. Since we know the middle angle is the same, knowing either other angles would give us this method as well.

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4 years ago
Which ones are true?​
Aleks [24]

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The first, third and last one are true

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