Question

Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which quadrant will the graph not go through and why?

Answer 1

Answer:

Quarderant 2

Step-by-step explanation:

Brainliest, please?

Answer 2

Answer:

2nd quadrant.

Step-by-step explanation:

The given function is

$h(x)=-6+\dfrac{2}{3}x$

We need to find the quadrant from which the graph of function is not passing.

At x=0,

$h(0)=-6+\dfrac{2}{3}(0)=-6$

So, y-intercept is (0,-6).

At h(x)=0,

$0=-6+\dfrac{2}{3}x$

$6=\dfrac{2}{3}x$

$18=2x$

$9=x$

So, x-intercept is (9,0).

It means the graph intersect negative side of y-axis and positive side of x-axis. When we join these two points, we get the graph is not passing through the 2nd quadrant.

Therefore, the required quadrant is 2nd quadrant.