Answer:
y = (4/7)x² - (24/7)(x)
Step-by-step explanation:
4 = a(-1)² + b(-1)
4 = a - b
0 = a(6)² + b(6)
36a + 6b = 0
b = -6a
4 = a - (-6a)
7a = 4
a = 4/7
b = -24/7
y = (4/7)x² - (24/7)(x)
Answer:
23) x= 3, y = 4
24) Any (x,y) values where x = 1.5 - 2y
Step-by-step explanation:
For the first system(23), it goes like this
[1 2 | 7]
[2 1 | 8]
We need to do L2 = L2 - 2L1, so now it is
[1 2 | 7]
[0 -3 |-6]
So, now we have:
-3y = -6 *(-1)
3y = 6
y = 2
x + 2y = 7
x + 4 = 7
x = 3
Now for system 24, we have:
[-1 2 | 1.5]
[2 -4| 3]
We do L2 = L2 + 2L1, so we have:
[-1 2 | 1.5]
[0 0| 0]
So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.
Answer:
Yes
Step-by-step explanation:
Pemdas
Parentheses
Answer: -11
