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ANEK [815]
3 years ago
9

Helpppppp Asapppp guys

Mathematics
2 answers:
Ksivusya [100]3 years ago
6 0
A d b then c

I think
alukav5142 [94]3 years ago
3 0

Answer:

-20\frac{3}{4} < -15\frac{1}{2} < -14\frac{3}{4} < -\frac{1}{4}

Step-by-step explanation:

Just so you know, the larger a negative number is, the smaller the number's value is.

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Can someone helppp meee
storchak [24]

Answer:

To find the radius, divide the diameter by 2;

V={π(r^2)h}/3

={3.14(4^2)*9 cm^3}/3

=3.14*16*3 cm^3

=150.72 cm^3

6 0
2 years ago
Drag each tile to the correct box. not all tiles will be used.
lana66690 [7]

Answer:

y=\frac{13}{6}x             y= \frac{11}{5}x          y = \frac{21}{9}x          y = \frac{19}{8}x

Step-by-step explanation:

Given

The attached graph

Required

Equations with higher unit rate

First, calculate the unit rate of the graph

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

(x_1.y_1) = (0,0)

(x_2.y_2) = (7,15)

So:

m = \frac{15 - 0}{7 - 0}

m = \frac{15}{7}

m = 2.143

For the given options.

The unit rate is the coefficient of x

So: y = \frac{19}{8}x

Going by the above definition of unit rate.

m = \frac{19}{8}

m = 2.375

y = \frac{27}{13}x

m = \frac{27}{13}

m = 2.077

y = \frac{21}{9}x

m = \frac{21}{9}

m = 2.333

y= \frac{11}{5}x

m= \frac{11}{5}

m= 2.20

y = \frac{15}{7}x

m = \frac{15}{7}

m = 2.143

y = \frac{31}{15}x

m = \frac{31}{15}

y = 2.067

y=\frac{13}{6}x

m=\frac{13}{6}

m=2.167

The unit rates grater than the graph's from small to large are:

y=\frac{13}{6}x             y= \frac{11}{5}x          y = \frac{21}{9}x          y = \frac{19}{8}x

m=\frac{13}{6}              m= \frac{11}{5}           m = \frac{21}{9}            m = \frac{19}{8}

4 0
3 years ago
Read 2 more answers
Find the length of the radius of the circle.
bearhunter [10]

Answer:

C)  6 inches

Step-by-step explanation:

(√72)² = x² + x²

72 = 2x²

72/2 = x²

36 = x²

√36 = √x²

6 = x

x = 6 inches

3 0
3 years ago
Read 2 more answers
PLEASE HELP
Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

please mark brainliest

4 0
2 years ago
Will mark brainliest
vovikov84 [41]
(0,0)-->(0,0)
(3,-1)-->(9,-3)
(3,3)-->(9,9)


so what you will plug after the dilation will be the points on the right/
hope i help
 
3 0
3 years ago
Read 2 more answers
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