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12345 [234]
3 years ago
9

Help plzzzzzzzzzzzzzz ​

Mathematics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

∠E

Step-by-step explanation:

∠E is between PE and EN

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Write greatest unit fractions that are repeating decimals. Then express each fraction as a decimal.
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Our repeating decimal would be= 0.5555….
Let’s give 0.5555….. repeating decimal a variable of x:
x= 0.5555…. or 0.5(move 1 point to the right)
So ,10x = 5.5555 or 5.5

Now, Let’s do subtraction:
10x = 5.5555… or 5.5  
<u>-   x =  0.5555… or 0.5</u>
 9x  = 5.0            or 5.0

To get a fraction, provide a denominator the same with the numerator of variable x which is 9. Then divide the difference:
<span><u>9x</u> = <u>5.0</u>  
9        9</span> <span> <span><span> <span> <span>Therefore, x = <u>5
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Carlos Martin received a statement from his bank showing a balance of $56.75 as of March 15. His checkbook shows a balance of $8
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3(x-1) help dawg please mate help me mates
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Step-by-step explanation:

3(x-1)

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3 years ago
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The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
4 years ago
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