Question

Two points on a line are (-10, 1) and (5,-5). If

Answer 1

Answer:

The x-coordinate is 0

Step-by-step explanation:

step 1

Find the slope  m of the line

we have the points

(-10, 1) and (5,-5)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{-5-1}{5+10}$

$m=\frac{-6}{15}$

Simplify

$m=-\frac{2}{5}$

step 2

Find the equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=-\frac{2}{5}$

$point\ (-10,1)$

substitute in the equation and solve for b

$1=-\frac{2}{5}(-10)+b$

$1=4+b$

$b=1-4=-3$

The equation of the line is

$y=-\frac{2}{5}x-3$

step 3

Find the x-coordinate of another point in the line if the y-coordinate is -3

For y=-3

substitute in the equation and solve for x

$-3=-\frac{2}{5}x-3$

$-3+3=-\frac{2}{5}x$

$0=-\frac{2}{5}x$

$x=0$

The point is (0,-3) -----> the y-intercept

therefore

The x-coordinate is 0