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3 years ago

What is the answer to Q=1/2p+15, for p

Mathematics

1 answer:

Mazyrski [523]3 years ago

7 0

Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500

p-intercept = -30/1 = -30.00000

q-intercept = 30/2 = 15

Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

p-(2*q-30)=0

Solve p-2q+30 = 0

we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties

Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000

q-intercept = 30/2 = 15

When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000

p-intercept = -30/1 = -30.00000

Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = 1.000/2.000 = 0.500

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Is (p3)4 • p8 = p20 true or false ?

Oduvanchick [21]

P3(4) = p12 them p12 * p8 = P160 (false)

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2 years ago

A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l

Y_Kistochka [10]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, 1), thus

y = a(x - 2)² + 1

To find a substitute (1, 0) into the equation

0 = a(1 - 2)² + 1

0 = a + 1 ( subtract 1 from both sides )

a = - 1

Hence

y = - (x - 2)² + 1 or

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3 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$