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4 years ago

A scientific law:

Physics

2 answers:

Natalija [7]4 years ago

4 0

Answer:

Explanation:

vladimir1956 [14]4 years ago

3 0

D. All of the above

This is true because scientific laws are all 3:
• They are well tested (to become a definite law)
• They are usually in equation form; for example: (e=mc^2)
• They are usually an example of a scientific model. The model generally will demonstrate the principle.

Hope this helps! ✅

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In your own words, explain what friction is

Andrew [12]

Answer:

Friction is a kind of force between two object when we rub or slide its surfaces together

for ex: when you rub the matchbox you get fire which is the result of friction

Explanation:

thats all i know

3 0

2 years ago

Read 2 more answers

Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit

Ede4ka [16]

Answer:

$386.2^{\circ}F$

Explanation:

We are given that

$P_1=200lbf/in^2$

$P_2=60lbf/in^2$

$v_1=200ft/s$

$v_2=1700ft/s$

$T_1=500^{\circ}F$

$Q=0$

$C_p=1BTU/lb^{\circ}F$

We have to find the exit temperature.

By steady energy flow equation

$h_1+v^2_1+Q=h_2+v^2_2$

$C_pT_1+\frac{P^2_1}{25037}+Q=C_pT_2+\frac{P^2_2}{25037}$

$1BTU/lb=25037ft^2/s^2$

Substitute the values

$1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}$

$500+1.598=T_2+115.4$

$T_2=500+1.598-115.4$

$T_2=386.2^{\circ}F$

7 0

4 years ago

the density of maple wood is about 755.kg/m. What is the mass of a solid piece of maple that has a volume 640.cm?

jenyasd209 [6]

I believe that the correct given values are:

density = 755 kg/m^3

volume = 640 cm^3

First let us convert volume to m^3 units.

volume = 640 cm^3 * (1 m / 100 cm)^3 = 6.4 x 10^-4 m^3

so the mass is:

mass = 755 kg/m^3 * (6.4 x 10^-4 m^3)

4 0

3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Vinil7 [7]

Answer:

Explanation:

7 0

3 years ago

A friend pushes a sled across horizontal snow and when it gets up to speed the friend jumps on. After the friend jumps on, the s

Shalnov [3]

Answer:

v’ =( $\frac{1}{1+ \frac{M}{m} }$ ) v

we see that the greater the difference, the more the sled slows down.

friction force

Explanation:

When the man pushes the sled he does work and the sled acquires a speed and as long as it is supplied with an energy equal to the work of the chipping force with the snow, the speed is maintained.

When he jumps on the sled, a collision occurs and the initial moment

p₀ = mv

is increased by the increase in mass

m_f= (m + M_{man} ) v '

In this case there is no longer any external force applied and the only external force is friction, which causes the sled to stop, even when it is small, but the significant reduction in speed is due to the increase in masses.

p₀ = p_f

mv = (m + M_{man}) v '

v ’= $\frac{m}{m+M}$ v

v’ =( $\frac{1}{1+ \frac{M}{m} }$ ) v

Therefore, we see that the greater the difference, the more the sled slows down.

The only forces that act on the sled with the man are the friction that is responsible for the decrease in speed and weight with the normal

4 0

3 years ago