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3 years ago

The scanner records the time from when a ultrasound wave is emitted to when its reflection is received

Physics

1 answer:

telo118 [61]3 years ago

3 0

Explanation:

The scanner records the time from when a ultrasound wave is emitted to when its reflection is received. A technician calculates the depth of the reflection using the equation as :

$\text{depth}=\dfrac{1}{2}\times \text{speed of ultrasound in patient}\times \text{time recorded by scanner}$

The distance covered by ultrasonic wave when it was emitted and gets reflected is 2d. Speed is given by :

$v=\dfrac{d}{t}$

d is distance and t is time

Here, d = 2d

So, the factor of (1/2) is used because the distance covered by the wave is 2 times when it was emitted and received.

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Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg

valentina_108 [34]

Answer:

-time it takes for the sled to come to a stop after launch of rocket = 7.244 s

-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m

Explanation:

From the question, looking at the motion while accelerating, we have;

Initial velocity; u = 0 m/s

Acceleration; a = 13.5 m/s²

Time; t = 3.3 s

Let's use first equation of motion to find final velocity (v).

v = u + at

v = 0 + (13.5 × 3.3)

v = 44.55 m/s

In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.

d1 = ut + ½at²

d1 = 0(3.3) + ½(13.5 × 3.3²)

d1 = 73.5075 m

Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².

Thus, from v = u + at, we can find the time it take for the sled to come to a stop.

Now, since it's coming to rest acceleration will be negative. Thus;

0 = 44.55 + (-6.15t)

0 = 44.55 - 6.15t

t = 44.55/6.15

t = 7.244 s

Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.

Thus, we'll use the equation;

v² = u² + 2as

Where s will be the second displacement which we will call d2.

Thus;

0² = 44.55² + (-2 × 6.15 × s)

0 = 1984.7025 - 12.3s

12.3s = 1984.7025

s = 1984.7025/12.3

s = 161.358

Thus, d2 = s = 161.358 m

Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;

= d1 + d2 = 73.5075 + 161.358 = 234.8655 m

4 0

4 years ago

Daisy walks across a force platform, and forces exerted by her foot during a step are recorded. The peak velocity reaction force

Len [333]

Answer:

(a). The resultant of these forces is 1216.55 N.

(b). The direction of the resultant forces is 80.53°.

Explanation:

Given that,

First force = 1200 N

Second force = 200 N

(a). We need to calculate the resultant of these forces

Using cosine law

$F=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}\cos\theta}$

Put the value into the formula

$F=\sqrt{1200^2+200^2+2\times1200\times200\cos90}$

$F=\sqrt{1200^2+200^2}$

$F= 1216.55\ N$

The resultant of these forces is 1216.55 N.

(b). We need to calculate the direction of the resultant forces

Using formula of direction

$\tan\alpha=\dfrac{F_{1}}{F_{2}}$

Put the value into the formula

$\alpha=\tan^{-1}(\dfrac{1200}{200})$

$\alpha=80.53^{\circ}$

Hence, (a). The resultant of these forces is 1216.55 N.

(b). The direction of the resultant forces is 80.53°.

4 0

3 years ago

Read 2 more answers

An engine causes a car to move 10 meters with a force of 100 N. The engine produces 10,000 J of energy. What is the efficiency o

gregori [183]

Answer:

10%

Explanation:

Efficiency = work done / energy used

e = (10 m × 100 N) / (10,000 J)

e = 0.1

The efficiency is 0.1, or 10%.

4 0

4 years ago

Which of the following devices would you expect to consume the most energy for each hour that it operates?

Nat2105 [25]

B. An electric space heater

4 0

3 years ago

A short ramp and a long ramp each reach a height of 1 m. Which

Pavel [41]

Answer:

he longer ramp has more mechanical advantage for it requires less force to push up a mass while being over a longer period of time. Its called Mechanical Advantage because say you had to lift a car up 1-meter. you cannot simply pick it up, but over a long enough slope you would be able to because you can apply a small force over a longer distance

Explanation:

5 0

3 years ago