Answer:
2.to every action there is always an equal & opposite reaction
<span>a) 13 seconds
b) 130 m/s
The formula for the distance an object moves while under constant acceleration is d = 1/2AT^2. So let's define d as 830 m, A as 9.8m/s^2, and solve for T
830 m = 1/2 9.8 m/s^2 T^2
830 m = 4.9 m/s^2 T^2
Divide both sides by 4.9 m/s^2
169.3878 s^2 = T^2
Take the square root of both sides
13.01491 s = T
Since we only have 2 significant figures, round the result to 13 seconds which is the answer to the first part of the question. To find out how fast the marble is moving, just multiply T and A together
13 s * 9.8 m/s^2 = 127.4 m/s
Since we only have 2 significant figures, round the result to 130 m/s.</span>
Answer:
C) Both 1 and 2
Explanation:
The scan tool may include a bi-directional control that allows the technician to control the output of the alternator for testing purposes.
The Diagnostic Trouble Codes (DTCs), are used by automobile manufacturers to diagnose problems related to the vehicle.
The scan tool can also be used to monitor the output voltage of the vehicle to verify if the correct amount of voltage is supplied by the alternator.
Both Technicians A and B are correct because the steps they both take are necessary for the diagnosis of the vehicle.
Answer:
C) To magnetize the needle
Explanation: I took the test!
Answer:
1.52 m
Explanation:
We are given that
Maximum force=F=679 N
Mass of rock ,m=385 kg
Distance,d=0.233 m
We have to find the minimum total length L of the rod required to move the rock.
Torque on rock=![T_1=mgd=385\times 9.8\times 0.233=879.11 N](https://tex.z-dn.net/?f=T_1%3Dmgd%3D385%5Ctimes%209.8%5Ctimes%200.233%3D879.11%20N)
Where ![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
Torque on man=![T_2=Force\times distance=(L-d)\times 679=(L-0.233)\times 679](https://tex.z-dn.net/?f=T_2%3DForce%5Ctimes%20distance%3D%28L-d%29%5Ctimes%20679%3D%28L-0.233%29%5Ctimes%20679)
![T_1=T_2](https://tex.z-dn.net/?f=T_1%3DT_2)
![(L-0.233)\times 679=879.11](https://tex.z-dn.net/?f=%28L-0.233%29%5Ctimes%20679%3D879.11)
![L-0.233=\frac{879.11}{679}=1.29](https://tex.z-dn.net/?f=L-0.233%3D%5Cfrac%7B879.11%7D%7B679%7D%3D1.29)
![L=1.29+0.233=1.523\approx 1.52 m](https://tex.z-dn.net/?f=L%3D1.29%2B0.233%3D1.523%5Capprox%201.52%20m)
Hence, the minimum total length of rod=1.52 m