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Svet_ta [14]
4 years ago
5

A 1313​-foot piece of string is cut into two pieces so that the longer piece is 44 feetfeet longer than twice the shorter piece.

If the shorter piece is x feet​ long, find the lengths of both pieces
Mathematics
1 answer:
Kitty [74]4 years ago
8 0

Answer:

423

Step-by-step explanation:

Start by setting up a formula.

x = the shorter piece

total = 1313

longer piece = (x*2) + 44

x + (x*2) + 44 = 1313

Simplify

3x + 44 = 1313

Now we must solve for x.

Whatever you do on the left side of the equal sign must also be done on the right.

The goal is to get x by itself on the left side.

Do the easiest thing first, which is usually addition or subtraction. In this case, subtract 44 from both sides.

3x + 44 - 44 = 1313 - 44

3x = 1269

Now the only way to cancel out the 3 on the left is to divide by 3. Since 3/3 =1. Remember this must be done on both sides to keep things equal.

3x/3 = 1269/3

x=423

The End

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horsena [70]

Answer:

1. Next sequence = 20

2. Tn = 47 - 3n

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Step-by-step explanation:

Given

Sequence 1: 0, 4, 8, 12, 16

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a. Write out the next sequence in (1)

The pattern followed by sequence 1 is that, each successive sequence is and addition of 4 to the previous sequence..

See observation below

4 = 0 + 4

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Definitely, the next sequence will be 4 + the previous sequence.

Next sequence = 16 + 4

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2. The rule for continuing sequence 2

It'll be observed that sequence 2 follows an arithmetic progression.

To get the rule for continuing the sequence, the following data are needed.

I. The first term of the sequence.

This is often represented by letter a.

a = 44

II. The common difference.

This is the difference between two successive sequence

This is often represented by letter d.

d = 41 - 44 = -3

Or

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Using the arithmetic progression formula

Tn = a + (n - 1)d

By substituting 44 for a and -3 for d.

Tn = 44 + (n - 1)(-3)

Tn = 44 - 3n + 3

Tn = 44 + 3 - 3n

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III. Work out a number in common in both sequence

It'll be observed that the visible data of sequence 2 are bigger than that of sequence 1.

To get a common number, we have to extend sequence 1 until we arrive at a common number in both sequence

Sequence 1: 0, 4, 8, 12, 16

This becomes

Sequence 1: 0, 4, 8, 12, 16, 20, 24, 28, 32.....

32 is common in sequence (1) and (2).

If the sequence is extended, we'll arrive at another common number. But we have to stop, since we've arrived at a common number.

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