Answer:
<em>Thus, the dimensions of the metal plate are 10 dm and 8 dm.</em>
Step-by-step explanation:
For a quadratic equation:

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.
We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:
P=2(L+W)=36
A=L.W=80
Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.
Thus we use the semi perimeter instead as P/2=L+W=18
The quadratic equation is, then:

Factoring by finding two numbers that add up to 18 and have a product of 80:

The solutions to the equation are:
x=10, x=8
Thus, the dimensions of the metal plate are 10 dm and 8 dm.
<span> lets say integrand is e^(y/x):
∫(x = 0 to 1) ∫(y
= 0 to x^2) e^(y/x) dy dx
= ∫(x = 0 to 1) xe^(y/x)
= ∫(x = 0 to 1) x(e^x - 1) dx
= ∫(x = 0 to 1) (xe^x - x) dx
= (xe^x - e^x) - (1/2)x^2
= 1/2. </span>
Answer:
Indubitably second option.
Step-by-step explanation:
Answer:
no solution
Step-by-step explanation:
- 2(v - 2) = - 3 - 2v ← distribute left side
- 2v + 4 = - 3 - 2v ( subtract 4 from both sides )
- 2v = - 7 - 2v ( add 2v to both sides )
0 = - 7 ← not possible
Hope this helps