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DanielleElmas [232]
3 years ago
10

Triangle A is the pre-image in a translation, and triangle B is the image, as shown below.

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0

Answer:

Your answer would be 6 units right.

Hope this was helpful!

Vika [28.1K]3 years ago
5 0

Answer:

six units right

Step-by-step explanation:

we know that

The point (-4,1) in the triangle A is translated to the point (2,1) in the triangle B

so

The rule of the translation is equal to

(x,y)-------> (x+6,y)

That means-------> The translation is six units to the right

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A five​-digit number starts with a number between 4​-9 in the first​ position, with no restrictions on the remaining 4 digits. a
Maurinko [17]

Answer:

(a) Pr = 0.3024

(b) Pr = 0.6976

(c) Pr = \frac{^9P_{n-1}}{10^{n-1}}

Step-by-step explanation:

Given

Start = \{5,6,7,8\} i.e. between 4 and 9

n(Start) =4

Digits = 5

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

First\ digit = 4 (i.e. any of the 4 start digits)

Second\ digit = 10\\ (i.e. any of the 10 digits 0 - 9)

Third\ digit = 10 (i.e. any of the 10 digits 0 - 9)

Fourth\ digit = 10 (i.e. any of the 10 digits 0 - 9)

Fifth\ digit = 10 (i.e. any of the 10 digits 0 - 9)

So, the total is:

Total = 4 * 10 * 10 * 10 * 10

Total = 40000

For selection that all digits are different, the selection is:

First\ digit = 4 (i.e. any of the 4 start digits)

Second\ digit = 9 (i.e. any of the remaining 9)

Third\ digit = 8 (i.e. any of the remaining 8)

Fourth\ digit = 7 (i.e. any of the remaining 7)

Fifth\ digit = 6 (i.e. any of the remaining 6)

So:

Selection =4 * 9 * 8 * 7 * 6

Selection =12096

So, the probability is:

Pr = \frac{Selection}{Total}

Pr = \frac{12096}{40000}

Pr = 0.3024

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

P(At\ least\ 1) = 1 - P(None)

So, we have:

Pr= 1 - 0.3024

Pr = 0.6976

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

Pr = \frac{Selection}{Total}

Where

Selection =4 * 9 * 8 * 7 * 6 ---- for selection of 5 i.e. n = 5

Total = 4 * 10 * 10 * 10 * 10

Selection =4 * 9 * 8 * 7 * 6

This can be rewritten as:

Selection = 4 * ^9P_4

4 can be expressed as: 5 - 1

So, we have:

Selection = (5-1) *^9P_{5-1}

Substitute n for 5

Selection = (n-1) *^9P_{n-1}

Selection = (n-1)^9P_{n-1}

Total = 4 * 10 * 10 * 10 * 10

This can be rewritten as:

Total = 4 * 10^4

Total = (5-1) * 10^{5-1}

Total = (n-1) * 10^{n-1}

Total = (n-1) 10^{n-1}

So, the expression is:

Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}

Pr = \frac{^9P_{n-1}}{10^{n-1}}

<em>Where n represents the digit number</em>

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2 years ago
22x(4+16)-78x3
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Answer:

what we solving for???? ill answer in the comments

Step-by-step explanation:

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Learning Task 3
ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. Distance = 3682km

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. L < 38m

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

Perimeter = 160

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

Perimeter = x + x + 1 + x + 2 + x + 3

This gives:

160 = x + x + 1 + x + 2 + x + 3

Collect Like Terms

160 -1-2-3= x+x+x+x

154= 4x

Divide both sides by 4

38.5 = x

x =38.5

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: Inzo = 10 + Miz

Five years ago: Miz - 5= \frac{1}{3} * (Inzo-5) --- (Missing from the question)

Required: Determine their present ages

Substitute 10 + Miz for Inzo in the second equation

Miz - 5 = \frac{1}{3} * (10 + Miz - 5)

Miz - 5 = \frac{1}{3} * (Miz + 5)

Multiply both sides by 3

3Miz - 15 = Miz + 5

Collect Like Terms

3Miz -Miz = 15  + 5

2Miz= 20

Divide both sides by 2

Miz = 10

Substitute 10 for Miz in Inzo = 10 + Miz

Inzo = 10 + 5

Inzo = 15

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

Speed = 100kph

Time = t

Local Train:

Speed = 45kph

Time = t + 45

Required: Determine the distance between A and B

Distance is calculated as:

Distance = Speed * Time

For the express train:

Distance = 100 * t

For the local train

Distance = 45 * (45 + t)

Distance between both stations are equal; So,

100 * t = 45 * (45 + t)

100 t = 2025 + 45t

Collect Like Terms

100 t -45t= 2025

55t= 2025

Divide by 55

t = 36.82

Substitute 36.82 for t in Distance = 100 * t

Distance = 100 * 36.82

Distance = 3682km

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: n + n + 2 > 24

Sum less than 60: n + n + 2 < 60

So, we have:

n + n + 2 > 24

2n + 2 > 24

Collect Like Terms

2n > 24-2

2n > 22

n > 11

n + n + 2 < 60

2n + 2< 60

Collect Like Terms

2n < 60-2

2n < 58

Divide by 2

n

So, we have:

n > 11 and n < 29

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

Perimeter < 152m

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

Perimeter =4 * L

Perimeter =4  L

So, we have:

4L < 152m

Divide through by 4

L < 38m

Hence, length is less than 38m (e.g. 37m)

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A rectangle has a vertices( 0,0) (3,0) and ( 0,6). what is the area of the rectangle
atroni [7]
18 units squared multiply 6 times 3 to get this answer- 18u^2
8 0
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