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shtirl [24]
3 years ago
14

Carol invested $2,560 into two accounts. One account paid 6% interest and the other paid 8% interest. She earned 7.25% interest

on the total investment in one year. How much money did she put in each account
Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

$960 into 6% account and $1600 into 8% account

Step-by-step explanation:

Let money put in 6% account be x

let money put in 8% account be y

How much interest did she earn?

2560 * 0.0725 = $185.6

Now, we can write:

0.06x + 0.08y = 185.6

and we know

x + y = 2560

We can say:

x = 2560 - y

and we put this into 1st equation:

0.06(2560 - y) + 0.08y = 185.6

153.6 - 0.06y + 0.08y = 185.6

0.02y = 32

y = 1600

and thus, x = 2560 - 1600 = 960

She put $960 into 6% account and $1600 into 8% account

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We can construct the function:

f(x)=2x

Where f(x) or y is ordinate and x is abscissa.

The function actually represents a line. Since it can have linear form.

f(x)=2x+0

Hope this helps.

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5 0
3 years ago
After how many years are the salaries offered by company a and company b the same
12345 [234]
24000 + 3000x = 30000 + 2400x
3000x - 2400x = 30,000 - 24,000
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6 0
3 years ago
In Janie's homeroom 54% of the students' families own a dog and 32% own a dog and a cat. What is the probability that a student'
pogonyaev

Answer:

51,111%

Step-by-step explanation:

We know that 45% have a dog but no cat.  While 23% have both a dog and a cat.

Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)

= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%

The probability that a student’s family owns a cat if the family owns a dog is 51,111%

6 0
3 years ago
Help me out? tysvm!!!
Sophie [7]

Answer: 103

Step-by-step explanation:

8 x 6.5 = 52,

52 + 8 = 60 (pints in total)

there are 2 cups in 1 pint so 60 x 2 = 120

120 - 17 = 103

3 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
GrogVix [38]

Answer:

  1. D. f^-1(x) = log2(x -6)
  2. 4x^2 -3 . . . . x ≤ 0
  3. B. √(x^5) -3√(x^3) -18√x

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

<em>Every term</em> will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

7 0
3 years ago
Read 2 more answers
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