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Karo-lina-s [1.5K]
3 years ago
9

Graph each piecewise function. Then identify the properties.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

Domain: (-∞, 0] U (0, ∞): All real numbers.

Range: (-∞, ∞)

Step-by-step explanation:

This function is composed of two polynomial functions, a quadratic whose domain is all real numbers and a negative slope whose domain is all real numbers.

Observe in the attached graph that the function is continuous for the whole domain, it does not have any jump. In addition, the parabolic function comes from ∞, then it has a minimum value in y = 1 it grows up to y = 4. Finally it joins with the equation of the line and it extends to -∞.

Then we can conclude that for this piecewise function:

Domain: (-∞, 0] U (0, ∞): All real numbers.

Range: (-∞, ∞)

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oscar bought some markers notebooks and packs of sticky notes for his office he bought the same number of markers as notebooks h
s2008m [1.1K]

The number of each kind of office supply oscar bought is = markers= (43.2 - 4.2y)/3 notebooks = (43.2-3x)/4.2, sticky notes = [43.2 - 4.2y)/3 + (43.2-3x)/4.2] + 3.

<h3>Calculation of total office supply</h3>

The number of markers he bought = X

The number of notebooks he bought= y

The number of sticky notes he bought= z= 3 + X+y

The amount he paid for markers = $1.05*X

The amount he paid for notebooks = $2.25*y

The amount he paid for sticky notes= $1.95 (3 + X+y)

The total amount he paid is = $49.05

That is;

$49.05 = $1.05x + $2.25y + $1.95 (3 + X+y)

$49.05 = $1.05x + $2.25y + $5.85 + $1.95x + $1.95y

$49.05 - $5.85 = 3x + 4.2y

$43.2 = 3x + 4.2y

Make X the subject of formula,

3x = 43.2 - 4.2y

X = (43.2 - 4.2y)/3

y= (43.2-3x)/4.2

z = [43.2 - 4.2y)/3 + (43.2-3x)/4.2] + 3

Learn more about addition here:

brainly.com/question/4721701

#SPJ1

4 0
2 years ago
Pls help i will mark brainliest!:) thank you!;D
pashok25 [27]
<h2><em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em></h2>

<em><u>H</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>g</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>B</u></em>

<em><u>T</u></em><em><u>o</u></em><em><u> </u></em><em><u>f</u></em><em><u>i</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>:</u></em><em><u> </u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>c</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>e</u></em><em><u>t</u></em><em><u>w</u></em><em><u>e</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>w</u></em><em><u>o</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>g</u></em><em><u>r</u></em><em><u>a</u></em><em><u>p</u></em><em><u>h</u></em><em><u> </u></em>

<em><u>=</u></em><em><u> </u></em>

<em><u>\sqrt{ {(x2 - x1)}^{2} }  +  \sqrt{ {(y2 - y1)}^{2} }</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>P</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>)</u></em>

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>,</u></em><em><u>6</u></em><em><u>)</u></em>

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<em><u>\sqrt{ {(0 - 0)}^{2} }  +  \sqrt{ {(6 - 3)}^{2} }</u></em>

<em><u>\sqrt{ {3}^{2} }</u></em>

<em><u>3</u></em>

So 3.0 is the distance

Hope it helps

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