It would be 1.65 in decimal form. convert it to fraction and thats your answer
Answer:
672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale
Step-by-step explanation:
No. of customers pass the display on the day of sale = 1462
Proportion of people will purchase if pass such a special display = 0.43
Mean = E(X)=np
E(X)=
E(X)=628.66
Standard deviation = 
Standard deviation =
Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale
P(X<x)=0.01
Using z table

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale
Hi there! :)
<h2>
20%</h2><h2>
</h2>
To solve, we can simply divide and multiply by 100 to solve for the percentage:
5 / 25 = 5 ÷ 25 = 1/5 or 0.20
Multiply the decimal by 100 to solve for the percentage:
0.20 × 100 = 20%
Answer:
Step-by-step explanation:
the event of drawing a spade card