Answer:
2
Step-by-step explanation:
ed
Answer:
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0 : p = 0.75 against H1: p > 0.75 One tailed test.
In this case H0 is not defined as p≤ 0.75 because the acceptance and rejection regions cannot be set up. Therefore we take the exact value of H0 : p= 0.75.
The claim is that the probability of the workers getting their job through the internet is greater than 75% or 0.75.
As H0 is supposed to be less than we choose H1 to be greater than equality.
It is the right answer........
<span>get all your x one on side and y on the opposing side
so we have
xdy=4ydx
dy/y=4dx/x
</span><span>integrate both sides
</span><span>lny=4lnx+C
</span><span> y=e^(4lnx+C)
</span><span>The answer is y=cx^4 </span>
