Do you have a calculator? you can solve it by substituting x.
y=16x^2
0: y = 16(0)^2 = 16(0) = 0
(x = 0 , y = 0)
0.5: y = 16(0.5)^2 = 16(0.25) = 4
(x = 0.5 , y = 4)
1: y = 16(1)^2 = 16(1) = 16
(x = 1 , y = 16)
1.5: y = 16(1.5)^2 = 16(2.25) = 36
(x = 1.5 , y = 36)
2: y = 16(2)^2 = 16(4) = 64
(x = 2 , y = 64)
2.5: y = 16(2.5)^2 = 16(6.25) = 100
(x = 2.5 , y = 100)
3 : y = 16(3)^2 = 16(9) = 144
(x = 3 , y = 144)
4: y = 16(4)^2 = 16(16) = 256
(x = 4 , y = 256)
if you multiply a negative number by itself, it will become positive. So, -4, -3, -2.5, -2, -1.5, -1, -0.5 will be the same as the positive 4, 3, 2.5, 2, 1.5, 1, 0.5.
I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.
Answer:
See Explanation
Step-by-step explanation:
<em>The question is incomplete as what is required of the question is not stated.</em>
<em>However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.</em>
Represent the distance from Atlanta to Colleyville with AC
Represent the distance from Atlanta to Bayville with AB
Represent the distance from Bayville to Colleyville with BC
So, we have that:


The relationship between AB, AC and BC is:

Make BC the subject of formula:


Convert fraction to decimal


<em>Hence, the distance from Bayville to Colleyville is 14.8 miles</em>
If 1 line completely overlaps the other line, they are the same line with infinite solutions.....so ur answer would be the 4th one
Answer:
8 + k² - 6 > 8(k + 2) - 4k when k = 7
Step-by-step explanation:
8 + k² - 6 = 8 + 7² - 6 = 51
8(k + 2) - 4k = 8(7 + 2) - 4(7) = 8(9) - 28 = 44
8 + k² - 6 > 8(k + 2) - 4k when k = 7
The distance formula is an algebraic expression used to determine the distance between two points with the coordinates (x1, y1) and (x2, y2).
<span><span>D=<span><span>(<span>x2</span>−<span>x1</span><span>)2</span>+(<span>y2</span>−<span>y1</span><span>)2</span></span><span>−−−−−−−−−−−−−−−−−−</span>√</span></span><span>D=<span>(<span>x2</span>−<span>x1</span><span>)2</span>+(<span>y2</span>−<span>y1</span><span>)2</span></span></span></span>
Example
Find the distance between (-1, 1) and (3, 4).
This problem is solved simply by plugging our x- and y-values into the distance formula:
<span><span>D=<span><span>(3−(−1)<span>)2</span>+(4−1<span>)2</span></span><span>−−−−−−−−−−−−−−−−−−</span>√</span>=</span><span>D=<span>(3−(−1)<span>)2</span>+(4−1<span>)2</span></span>=</span></span>
<span><span>=<span><span>16+9</span><span>−−−−−</span>√</span>=<span>25<span>−−</span>√</span>=5</span><span>=<span>16+9</span>=25=5</span></span>
Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.
If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:
<span><span>(<span><span><span>x1</span>+<span>x2</span></span>2</span>,<span><span><span>y1</span>+<span>y2</span></span>2</span>)</span><span><span>(<span><span><span>x1</span>+<span>x2</span></span>2</span>,<span><span><span>y1</span>+<span>y2</span></span>2</span>)</span><span>
</span></span></span>