Answer:
the horizontal distance is the x-intercept, and the vertical distance is the y-intercept
1) x-int=1, y-int=1
2) x-int=6, y-int=5
Answer:
![\bar X = \frac{0.4+0.2+0.4+0.6}{4}= 0.4](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B0.4%2B0.2%2B0.4%2B0.6%7D%7B4%7D%3D%200.4)
Now we can calculate the absolute deviations from the mean for each value:
|0.4-0.4|=0
|0.2-0.4|=0.2
|0.4-0.4|=0
|0.6-0.4|=0.2
And adding these 4 values and dividing by 4we got the MAD on this case:
![MAD = \frac{0+ 0.2+0 +0.2}{4}=0.1](https://tex.z-dn.net/?f=MAD%20%3D%20%5Cfrac%7B0%2B%200.2%2B0%20%2B0.2%7D%7B4%7D%3D0.1)
Step-by-step explanation:
We have the following dataset given:
0.4,0.2,0.4,0.6
In order to calculate the MAD we need to calculate the sample mean first with this formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
Replacing we got:
![\bar X = \frac{0.4+0.2+0.4+0.6}{4}= 0.4](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B0.4%2B0.2%2B0.4%2B0.6%7D%7B4%7D%3D%200.4)
Now we can calculate the absolute deviations from the mean for each value:
|0.4-0.4|=0
|0.2-0.4|=0.2
|0.4-0.4|=0
|0.6-0.4|=0.2
And adding these 4 values and dividing by 4we got the MAD on this case:
![MAD = \frac{0+ 0.2+0 +0.2}{4}=0.1](https://tex.z-dn.net/?f=MAD%20%3D%20%5Cfrac%7B0%2B%200.2%2B0%20%2B0.2%7D%7B4%7D%3D0.1)
The second one and the last one