A) probability of sequences can be calculated by multiplying the probability of the first event by the second, etc. until the end of the series. Thirteen cards are clubs in a 52 card deck, so the initial probability of drawing a club is 13/52, or 0.25 (25%). This means that the cumulative probability is 0.25 x 0.25, or 0.0625 (6.25%).
B) Like part a, the initial probability of finding a green marble is 6/16, or 0.375 (37.5%). When not replacing the marble, the second probability is now 5/15, or 0.33 (33.3%), due to the loss of this marble. This means that the cumulative probability is 0.375 x 0.333, or 0.1249 (12.49%).
C) The initial probability of finding a green apple is 4/6, or 0.66 (66.6%). The second probability, when not replacing the apple is now 2/5, or 0.4 (40%) - the loss of the apple affected the total number of apples, but didn’t affect the number of red apples. This means that the cumulative probability is 0.666 x 0.4, or 0.266 (26.6%).
D) Unfortunate, I don’t know what the problem is asking, so I can’t answer this for you.
I’ll assume the question is asking us to factor the above polynomial:
5x^2 + 10x - 45
Factor out a 5:
5(x^2 + 2x - 9)
This appears to be an irreducible quadratic polynomial, so let’s leave it alone.
5x^2 + 10x - 45 = 5(x^2 + 2x - 9)
Area: Trapezoids A = ½h(b1<span> + b</span>2<span>)
</span>Rhombuses A=pq/2
Kites A=pq/2
Answer:
u
Step-by-step explanation:
in which class. do uuuu
Answer:
x = 3/2 or x = -4
Step-by-step explanation:
The identifiable error the students have is that before the left hand side of the equation is factorized, the right hand side value of 12 ought to be brought to the left hand side, leaving a net value of zero on the right hand side. Then whatever is factored on the left hand side is then equated to zero and then we can find the two values of x after setting each of the individual factors to zero
We proceed as follows;
