A towns population went from 25,800 to 42600 what was the percent of change
2 answers:
The question is asking us to find the percent of change of a town's population. Initially, the population was 25,800. After, the town's population was 42,600 people. We can use a proportion to find the percent increase. Here is what our setup should look like:
Now, just solve for x. We can do this by using cross multiplication and simplifying. This results in x being 165.1. Therefore, the answer to your query is that the town population's percent of change is 165.1 percent increase.
Now, just solve for x. We can do this by using cross multiplication and simplifying. This results in x being 165.1. Therefore, the answer to your query is that the town population's percent of change is 165.1 percent increase.
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Answer:
The probability that the sample will contain exactly 0 nonconforming units is P=0.25.
The probability that the sample will contain exactly 1 nonconforming units is P=0.51.
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Step-by-step explanation:
We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.
We can write the probability mass function as:
where k is the number of non-conforming units on the sample of n=4.
We can calculate the probability of getting no non-conforming units (k=0) as:
We can calculate the probability of getting one non-conforming units (k=1) as: