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2 years ago

All Philippines Tamaraw are Mammals What is the statements

Mathematics

1 answer:

Rasek [7]2 years ago

7 0

Answer:

The tamaraw or Mindoro dwarf buffalo (Bubalus mindorensis) is a small hoofed mammal belonging to the family Bovidae. It is endemic to the island of Mindoro in the Philippines, and is the only endemic Philippine bovine.

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How do defined terms and undefined terms relate to each other ?

dalvyx [7]

<span>In geometry, definitions are formed using known words or terms to describe a new word. There are three words in geometry that are not formally defined. These three undefined terms are point, line and plane. Undefined terms have not been defined, and defined are answered. They are terms that have a relationship with the point od discussion. :)</span>

7 0

2 years ago

Name 2 same side interior angles

Leokris [45]

Answer:

Transversal and Consecutive

7 0

3 years ago

Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u

Tamiku [17]

Answer:

Step-by-step explanation:

15. $\frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx} \\$

16. $\frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }$

$=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2} \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\$

=> The clause is correct

17. Do the same (16)

18. $\frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx$

19.

$\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\$

=> The clause is correct

20. Do the same (18)

21. Left = $\frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA} } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}$

Right = $cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA} \\$

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

5 0

3 years ago

Make y the subject of each of y-p=m

Serga [27]

Answer:

y=m+p

Step-by-step explanation:

take the p to the other side.

p crosses = sighn and becomes +

hence ans = y=m+ p

6 0

3 years ago

Find the third term of the geometric sequence when a1=1/4 and r=−2

Jobisdone [24]

Answer:

1 is the third term.

Step-by-step explanation:

Geometric sequences have a common ratio. This means a term divided by previous term is the same no matter the choosing of term.

So for example:

$\frac{a_{n}}{a_{n-1}}=\frac{a_{n-1}}{a_{n-2}}=\cdots=\frac{a_4}{a_3}=\frac{a_3}{a_2}=\frac{a_2}{a_1}$

So anyways geometric sequences means you are just multiply the common ratio over and over to generate the next term.

So, the first term is 1/4.

The second term is (-2)(1/4)=-1/2.

The third term is (-2)(-1/2)=1.

7 0

3 years ago