Answer: (x2 – 1) – 5(x – 1)
Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:
In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K:
6x - 31 = 11x + 64
6x cancels out and you take 6x away from 11x
-31 = 5x + 64
64 cancels out and you take 64 away from -31
-95 = 5x
Divide both sides by 5
-19 = x
<u><em>Answer:</em></u>
y^2 = 28x
<em><u>Step-by-step explanation:</u></em>
Since the directrix is horizontal, use the equation of a parabola that opens left or right.
(y−k)^2 = 4p(x−h)
Find the vertex.
(0,0)
Find the distance from the focus to the vertex.
p = 7
Substitute in the known values for the variables into the equation
(y−k)^2 = 4p(x−h).
(y−0)^2 = 4(7)(x−0)
Simplify.
<em>y^2 = 28x</em>
Answer:
arc ABC = 196°
∠DCQ = 47°
Step-by-step explanation:
arc AD = 70°
∠D = 1/2 arc ABC = 98°
arc ABC = 98° * 2 = 196°
arc CD = 360° - arc AD - arc ABC = 360°-70°-196° = 94°
tangent chord angle DCQ = 1/2 arc CD = 1/2 * 94° = 47°