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MaRussiya [10]
3 years ago
8

Write the equation of the line in slope-intercept form.

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0
Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2

slope of the req. line = -1/2

equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y  = (-1/2)x

this is your req. equation of line.
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Given that e = 4f + 1, and e = 3f + 5, this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).

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Nice and simple question we have here! The step that can be used to find the solution should be 4f + 1 = 3f + 5.

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Answer:

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