The function f(x) = 2.5x + 75 is used to model the cost

Musya8 [376]

I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music

5 0

2 years ago

The volume of a room is 640 cubic feet. If the length is 10 feet and the width is 4 feet, find the heigh

Allisa [31]

Answer:

16

Step-by-step explanation:

10 · 4 = 40

640/40= 16

4 0

2 years ago

Can anyone do 4.503 times 8.04

Natali [406]

Answer:

The answer is 36.20 :)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0

Westkost [7]

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

8 0

1 year ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago