The quadrant would be the first one, because once reflected over the y-axis, it would become (2,-8), and once reflected over the x-axis, it would become (2,8)
Given:
The two points are (-5,8) and (-3,1).
To find:
The distance between the given two points in simplest radical form.
Solution:
Distance formula: The distance between two points is
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Using distance formula, the distance between (-5,8) and (-3,1) is
![d=\sqrt{(-3-(-5))^2+(1-8)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-3-%28-5%29%29%5E2%2B%281-8%29%5E2%7D)
![d=\sqrt{(-3+5)^2+(-7)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-3%2B5%29%5E2%2B%28-7%29%5E2%7D)
![d=\sqrt{(2)^2+(-7)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%282%29%5E2%2B%28-7%29%5E2%7D)
![d=\sqrt{4+49}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B4%2B49%7D)
![d=\sqrt{53}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B53%7D)
Therefore, the distance between two points (-5,8) and (-3,1) is
units.
Parenthises
Exponent
Multiply
Divide
Add
Subtract
The answer is true because it comes before subtraction in the phrase PEMDAS.
9u means you're multiplying 9 into that vector, both components. Same with the 2v. 9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>. Now let's do v. 2* -6 (twice) = -12, so your new v vector is <-12, -12>. Add those together now, first components of each and second components of each. 27 + (-12) = 15; -9+(-12)=-21. So the addition of those gives us a final vector with a displacement of <15, -21>
Step-by-step explanation:
5×6'3n=20
30'3n=20
3n=20-30
3n/3= -10/3
n= -3