By using any two of the points in the table, we will see that the slope is -2.
<h3>How to get the slope for the linear relationship?</h3>
A general linear relationship is:
y = a*x + b
Where a is the slope and b is the y-intercept.
Remember that if the line passes through (x₁, y₁) and (x₂, y₂), the slope is:
Here we can use the first two points on the table:
(-4, 11) and (2, -1), so the slope is:
Then the slope of the line is -2.
If you want to learn more about linear relationships:
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Answer:
see below
Step-by-step explanation:
I enter the equation into a graphing calculator and let it do the graphing.
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If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.
Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).
I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).
Of course, you don't plot any function values for x > 4.
