The point-slope form of the equation for a line through point (h, k) with slope m is ...
y - k = m(x - h)
For your given point and slope, this equation is
y + 1 = -1(x + 10)
Answer:
The height of the ball is the same after 1.5 seconds and 3.5 seconds. ⇒ (A)
Step-by-step explanation:
<em>The quadratic function is represented by a parabola</em>
- The parabola is symmetric about its vertex.
- The average of the x-coordinates of any opposite points (points have the same y-coordinates) on the parabola is equal to the x-coordinate of its vertex point.
- The axis of symmetry of it passes through the x-coordinate of its vertex point.
- The equation of its axis of symmetry is x = h, where h is the x-coordinate of its vertex point.
∵ The quadratic function modeling the height of a ball over time
∴ f(t) = at² + bt + c
→ t is the time in second, f(t) is the height of the ball after t seconds
∵ It is symmetric about the line t = 2.5
∴ The x-coordinate of its vertex is 2.5
→ That means the average of the x-coordinates of any two
opposite points belong to f(t) is 2.5
∵ The average of 1.5 and 3.5 =
∴ 1.5 and 3.5 have the same value of f(t)
∴ 1.5 and 3.5 have the same height
The height of the ball is the same after 1.5 seconds and 3.5 seconds.
2.96 or 18.75 is the answer im leaning towards 2.96 though
The slope(m) is 2/3
Passes through (3,4)
Take a second point (x,y)
Slope(m) = Change in y-axis divide by change in x-axis
(y-4) ÷ (x-3) = 2/3
y - 4 = 2/3x - 2
y = 2/3x + 2
Answer:
x + 43 = 72.98
<u> - 43 - 43</u>
x = 29.98
Step-by-step explanation: