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3 years ago

What are two ratios that are equivalent to 12:20?

Mathematics

2 answers:

arlik [135]3 years ago

7 0

Answer: 3 : 5 and 6 : 10

Explanation: First rewrite the ratio 12 : 20 as the fraction 12/20.

Next, we can find an equal ratio by

simply writing this fraction in lowest terms.

If we divide both the numerator and denominator of 12/20

by their greatest common factor of 4, we get the equal ratio 3/5.

Now we can use 3/5 to find another equal ratio.

If we multiply both the numerator and denominator

of 3/5 by 2, we get the equal ratio 6/10.

So 12 : 20 is equal to 3 : 5 and 6 : 10.

Make sure to write your final answers

using the same form as the original problem.

Andrei [34K]3 years ago

4 0

Answer:

24:40, and 6:10

Step-by-step explanation:

I hope my answer was helpful and accurate! Have a blessed day!!

P.S may I please have brainliest if my answers deserves it, I don't normaly ask I currently have enought points but not enough brainliest to level up

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If the top of a 4.50 m ladder reaches twice as far up a vertical wall as the foot of the

STALIN [3.7K]

Answer:

4 m.

Step-by-step explanation:

Length of ladder, L = 4.50 m

Base of ladder from the wall, B = x

Height of the wall, H = 2x

Using Pythagoras theorem

$L^2 = B^2 + H^2$

$4.5^2 = x^2 + (2x)^2$

$5x^2 = 4.5^2$

$x = 2\ m\ (approx.)$

Height of the wall is equal to 2 x 2 = 4 m.

6 0

3 years ago

Due tomorrow !!! Ugh

Y_Kistochka [10]

1.) 2
2.) 5
3.)84
4.) 4
5.) 31
6.).5

7 0

3 years ago

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$