1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fredd [130]
3 years ago
11

The population of Buhlerville is 92,000 in 2019. The population of the city was 94880 in 2021. What is the

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

Your answer

97850.156

Mark it as Brainlist answer. Follow me to get more answer

Step-by-step explanation:

You might be interested in
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
A sailor is 30m above the water in the crow's nest on a sailboat. The sailor encounters an orca surface at an angle of depressio
Natali [406]

Given :

A sailor is 30 m above the water in the crow's nest on a sailboat.

The sailor encounters an orca surface at an angle of depression of 15 degrees.

The crows nest is 20 m horizontally from the bow (front) of the boat.

To Find :

How far in front of the boat is the orca.

Solution :

Let, distance of boat front from the crow's nest is x.

So,

\dfrac{30}{20+x}=tan \ 15^{\circ}\\\\x=\dfrac{30}{tan \ 15^{\circ}}-20\\\\x=111.94-20\\\\x=91.94\ m

Hence, this is the required solution.

4 0
2 years ago
2x+4≥24 how do I solve this problem
Katen [24]
First subtract 4 then divide 2 so u can isolate x
3 0
3 years ago
What's the value of x?
Nutka1998 [239]
It is a definitely your welcome
8 0
2 years ago
Solve using the Quadratic Formula.<br><br> 3x2 + 2x + 1 = 0
Crazy boy [7]

Answer:

Hi! The correct answer is x= -7/2

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x.

8 0
2 years ago
Other questions:
  • What is 4 (1/2+ 5/4) + -5=
    12·1 answer
  • Determine the domain of the function
    12·2 answers
  • Sara needs to take a taxi to get to the movies. The taxi charges $4.75 for the first mile, and then $2.25 for each mile after th
    8·1 answer
  • What is 1,537x242?<br> You can get ten points by answering this plz help me.
    5·2 answers
  • Really need help<br> Hurryyyyyyy
    6·1 answer
  • What is the slope of the line through (-9,6) (-6,-9)
    6·1 answer
  • PLZZZZZZZZZ HELP THANK YOUUUUUUUU !!!!!
    7·1 answer
  • If y(x) = 4x, what is x when y(x) = 4<br><br> A. 1<br><br> B. 4<br><br> C. 2<br><br> D. 0
    12·1 answer
  • Pls help. I'll mark you as brainliest.
    14·2 answers
  • The function fis given by this table of values.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!