All categories

3 years ago

What is the answer of this

Mathematics

2 answers:

Dominik [7]3 years ago

7 0

For 13. the answer is w = -1.

Here are the steps

1. subtract 5 from both sides ( 3w = 2 - 5)

2. simplify 2 - 5 to -3 (3w = -3)

3. divide both sides by 3 ( finally the answer is w = -1.
)

il63 [147K]3 years ago

5 0

3W+5=2
3w=2-5
3w=-3
w=-1

You might be interested in

Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).

Marina86 [1]

Given:

The given equation is:

$y=-4x+3$

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

$y=mx+b$

Where, m is slope and b is y-intercept.

We have,

$y=-4x+3$

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

$m\times (-4)=-1$

$m=\dfrac{-1}{-4}$

$m=\dfrac{1}{4}$

The slope of required line is $m=\dfrac{1}{4}$ and it passes through the point (4,-1). So, the equation of the line is:

$y-(-1)=\dfrac{1}{4}(x-4)$

$y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}$

$y=\dfrac{1}{4}x-1-1$

$y=\dfrac{1}{4}x-2$

Therefore, the equation of the required line is $y=\dfrac{1}{4}x-2$ .

5 0

2 years ago

Fill in the table with the cost to swim the given number of days. Each amount should be the total cost to swim that number of da

Lesechka [4]

Answer:

y = 0x + 70

y = 4x + 15

y = 6x + 0

Step-by-step explanation:

6 0

3 years ago

3. Which equation matches the statement "The product of 3 and the difference of a number and 10

Ann [662]

Answer:

3(x-10)=15

Step-by-step explanation:

assuming 152 is a typo

4 0

2 years ago

If a/3 = b/2 , what are the following ratios? 5a:3b

Arlecino [84]

15 = 6 I hope this is what you are looking for

5 0

3 years ago

Read 2 more answers

Solve the following differential equations using classical methods. Assume zero initial conditions.

MA_775_DIABLO [31]

I'll use the integrating factor method for the first DE, and undetermined coefficients for the second one.

(a) Multiply both sides by exp(7t ):

exp(7t ) dx/dt + 7 exp(7t ) x = 5 exp(7t ) cos(2t )

The left side is now the derivative of a product:

d/dt [exp(7t ) x] = 5 exp(7t ) cos(2t )

Integrate both sides:

exp(7t ) x = 10/53 exp(7t ) sin(2t ) + 35/53 exp(7t ) cos(2t ) + C

Solve for x :

x = 10/53 sin(2t ) + 35/53 cos(2t ) + C exp(-7t )

(b) Solve the corresonding homogeneous DE:

d²x/dt ² + 6 dx/dt + 8x = 0

has characteristic equation

r ² + 6r + 8 = (r + 4) (r + 2) = 0

with roots at r = -4 and r = -2. So the characteristic solution is

x (char.) = C₁ exp(-4t ) + C₂ exp(-2t )

For the particular solution, assume an ansatz of the form

x (part.) = a cos(3t ) + b sin(3t )

with derivatives

dx/dt = -3a sin(3t ) + 3b cos(3t )

d²x/dt ² = -9a cos(3t ) - 9b sin(3t )

Substitute these into the non-homogeneous DE and solve for the coefficients:

(-9a cos(3t ) - 9b sin(3t ))

… + 6 (-3a sin(3t ) + 3b cos(3t ))

… + 8 (a cos(3t ) + b sin(3t ))

= (-a + 18b) cos(3t ) + (-18a - b) sin(3t ) = 5 sin(3t )

So we have

-a + 18b = 0

-18a - b = 5

==> a = -18/65 and b = -1/65

so that the particular solution is

x (part.) = -18/65 cos(3t ) - 1/65 sin(3t )

and thus the general solution is

x (gen.) = x (char.) + x (part.)

x = C₁ exp(-4t ) + C₂ exp(-2t ) - 18/65 cos(3t ) - 1/65 sin(3t )

7 0

3 years ago