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4 years ago

The 5 in 6.052 has 1/10 the value of the 5 in?

1 answer:

6 0

60.52

to find 1/10 of the value before 5 in, multiply 10 (or move the decimal point to the right once) to find the right answer

1/10 of 5 in is 0.5 in

hope this helps

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What equation can relate to this sentence 11 is the quotient of a number y and 6 ?

Natalija [7]

Answer: 11 = y ÷ 6

Step-by-step explanation: since the problem says 11 is that means the equation equals 11 and when it says quotient that means that the equation must include division.

4 0

4 years ago

Which inequality statement best represents the graph?

I am Lyosha [343]

Answer:

f(x) < –x2 + x – 1

Step-by-step explanation:

The graph is going down so we know that there is a maximum, therefore the A value has to be negative. This rules out f(x) < x2 + x – 1 and f(x) > x2 + x – 1 . The shaded area of the graph is below which indicates that f(x) has to be less than the function. This means the correct answer is f(x) < –x2 + x – 1 .

7 0

4 years ago

Read 2 more answers

Does anyone know how to do this please help me

Anit [1.1K]

Answer:

162°

Step-by-step explanation:

a circle has 360°, or the angle of a whole circle is that

so 45% of 360 =

0.45 times 360 = 162

7 0

3 years ago

6) The amount of Jen's monthly phone bill is normally distributed with a mean of $70 and a standard

alexandr402 [8]

Answer:

i)The correct option is D.) 99.74%

ii) The correct option is B.) 68.26%

Step-by-step explanation:

i) P(10≤X≤70) = P( (10−40)/10 ≤Z≤ (70−40 )/10 ) = Pr(−3≤Z≤3)

= 0.9987 - 0.0013 = 0.99734

Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%

ii)P(2.1≤X≤3.1) = P( (2.1 − 2.6) /0.5 ≤ Z ≤ (3.1−2.6 )/0.5) = Pr(−1 ≤Z ≤1) )

= 0.8413 − 0.1587 = 0.6826

Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%

5 0

3 years ago

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

8 0

3 years ago