Answer:

Step-by-step explanation:
we are given

we can simplify left side and make it equal to right side
we can use trig identity


now, we can plug values

now, we can simplify



now, we can factor it

![\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%28sin%5E2%28a%29%2Bcos%5E2%28a%29-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can use trig identity

![\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%281-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can cancel terms

now, we can simplify it further




now, we can use trig identity

we can replace it

so,

Solution:
As we given that
then using this conversion factor we can write 
and further it can be written as

Hence the required conversion factor is 2.54 cm/1 inch as we can see from the above calculation.
Answer:
The confidence interval for 90% confidence would be narrower than the 95% confidence
Step-by-step explanation:
From the question we are told that
The sample size is n = 41
For a 95% confidence the level of significance is
and
the critical value of
is 
For a 90% confidence the level of significance is
and
the critical value of
is 
So we see with decreasing confidence level the critical value decrease
Now the margin of error is mathematically represented as
given that other values are constant and only
is varying we have that

Hence for reducing confidence level the margin of error will be reducing
The confidence interval is mathematically represented as

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower
I can see it, it's too blurry and small
Answer:
d
Step-by-step explanation:
an equation always shows that sum is equal
in this case 1825026 will subtract 17 and the remainder will be used to find A