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3 years ago

2x+3/4(4x+16)=7 I need help finding x.. I don’t know how to do these problems with fractions :(

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Answer:

x=-1

Step-by-step explanation:

2x+3/4(4x+16)=7

2x+(3x12)=7--->distributive property

2x+3x+12=7

5x+12=7--->addition property

5x=-5--->subtraction peroperty

x= -1---?division property

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Answer:

Total number of employees = 86,891 employees

Step-by-step explanation:

Let

x = total number of employees

26.7% of x = 23,200

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3 years ago

Amanda has a recipe that requires 3 1/2 cups of milk. If she is only making 2/3 of the recipe, how many cups of milk will she ne

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Answer:

2 1/3

Step-by-step explanation:

She will need 2/3 of 3 1/2:

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3 years ago

1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . .

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3 years ago

Evaluate rs + 14s when r = 6 and s = 8

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Answer:

160

Step-by-step explanation:

Plug in 6 for r, and 8 for s in the expression:

(r)(s) + (14)(s) = (6)(8) + (14)(8)

Remember to follow PEMDAS. First, multiply, then add:

(6 * 8) + (14 * 8)

48 + 112

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3 years ago

Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

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Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

Perpendicular² + Base² = Hypotenuse².

Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² = Hypotenuse².

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0

3 years ago

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