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3 years ago

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Amy has a total of 560 marbles, She has five times as many small marbles as medium marbles. The number of large marbles is two m

ore than three times the number of medium marbles. How many of each size does she have?

1 answer:

Klio2033 [76]3 years ago

7 0

I am sorry if answer is wrong,reply me

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Assume that adults have IQ scores that are normally distributed with a mean of mu equals 105 and a standard deviation sigma equa

Sindrei [870]

Answer:

0.7698

Step-by-step explanation:

If you call your random variable $X$ , then what you are looking for is

$P(87 \leq X \leq 123)$

because you want the probability of $X$ being <em>between 87 and 123.</em>

We need a table with of the normal distribution. But we can only find the table with $\mu = 0$ and $\sigma = 1$ . Because of that, first we need to <em>normalize </em>our random variable:

$Z = \frac{X - \mu}{\sigma} = \frac{X - 105}{15}$

(you can always normalize your variable following the same formula!)

now we can do something similar to our limits, to get a better expression:

$\frac{87 - 105}{15} = \frac{-18}{15} = -1.2$

$\frac{123 - 105}{15} = \frac{18}{15} = 1.2$

And we transform our problem to a simpler one:

$P(87 \leq X \leq 123) = P(-1.2 \leq Z \leq 1.2) = P(Z \leq 1.2) - P(Z \leq -1.2)$

(see Figure 1)

From our table we can see that $P(Z \leq 1.2) = 0.8849$ (this is represented in figure 2).

Remember that the whole area below the curve is exactly 1. So we can conclude that $P(Z \geq 1.2) = 0.1151$ (because 0.8849 + 0.1151 = 1). We also know the normal distribution is symmetric, then

$P(Z \leq -1.2)= P(Z \geq 1.2) = 0.1151$ .

FINALLY:

$P(Z \leq 1.2) - P(Z \leq -1.2) = 0.8849 - 0.1151 = 0.7698$

5 0

3 years ago

100 POINTS PLEASE HELP ASAP!!!!!!

Scorpion4ik [409]

Answer:

they spent 20.3 hours every week watching television!

Step-by-step explanation:

Hope it helped :) please mark brainliest :)

3 0

3 years ago

What is the product of (3 the square root of 8)(4 the square root of 3)? Simplify your answer

Vsevolod [243]

$3\sqrt{8}\cdot4\sqrt{3} \\12\sqrt{24} \\12\cdot2\sqrt{6} \\\boxed{24\sqrt{6}}$

8 0

3 years ago

A brace for a shelf has the shape of a right triangle. Its hypotenuse is 10 inches long and the two legs are equal in length. Ho

vagabundo [1.1K]

This is a classic example of a 45-45-90 triangle: it's a right triangle (one angle of 90) & two other sides of the same length, which means two angles of the same length (and 45 is the only number that will work). With a 45-45-90 triangle, the lengths of the legs are easy to determine:
45-45-90
1-1-sqrt2
Where the hypotenuse corresponds to sqrt2.
Now, your hypotenuse is 10.
To figure out what each leg is, divide 10/sqrt2 (because sqrt2/sqrt2 = 1, which is a leg length in the explanation above).
Problem: you can't divide by radicals. So, we'll have to rationalize the denominator:
(10•sqrt2)/(sqrt2•sqrt2)
This can be rewritten:
10sqrt2/sqrt(2•2)
=10sqrt2/sqrt4
=10sqrt2/2
=5sqrt2 Hope this helps!!

3 0

3 years ago

Prepare a perpetual inventory record, using the FIFO inventory costing method, and determine the company's cost of goods sol

krek1111 [17]

Answer:

The First-In, First-Out (FIFO) inventory costing method assumes that the inventory items ordered first are the first ones sold.

Step-by-step explanation:

The First-In, First-Out inventory costing method assumes that the inventory items ordered first are the first sold. This is ideal for goods that are highly perishable, for example fresh milk. Since no figures or dates are given, we will assume that the month is March 2019 and use any figures to make the example.

Date Item Quantity of stock Cost Price

01 Opening stock bought on Feb 28 10 100

05 Sale of 5 goods (cost is $10 each) (5) 50

15 Purchase of stock (20 goods at $20 each) 20 400

25 Sale of 15 goods (15) 250

(5 at $10 each & 10 at $20 each)

31 Closing Stock 10 200

(20 goods bought on 15th - 10 goods sold on 25th)

The quantity on hand at the end of the month is 10 units.

Total cost of goods on hand at end of the month = 10 units * $20 = 200.

Total cost of goods purchased during the month = $20 * 20 units = $400

Total cost of goods sold during the month = [($10 *5) + ($10 * 5)+ ($20 * 10)] = $200

6 0

3 years ago