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Ber [7]
1 year ago
9

An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. If the total cost was $1825.00, how

many shares of each stock did the investor buy? (Round to two decimal places if necessary.)
Mathematics
1 answer:
statuscvo [17]1 year ago
7 0

The shares of $2.25 are 200 and the shares of $2.75 are 700.

According to the question,

We have the following information:

An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. And the total cost was $1825.00.

Now, let's take the shares of $2.25 to be x and the shares of $2.75 to be y.

So, we have the following expression:

x+y = 700

x = 700-y ....(1)

2.25x+2.75y = 1825 ...(2)

Putting the value of x from equation 1:

2.25(700-y)+2.75y = 1825

1575-2.25y+2.75y = 1825

1575+0.5y = 1825

0.5y = 250

y = 250/0.5

y = 500

Now, putting the value of y in equation 1:

x = 700-y

x = 700-500

x = 200

Hence, the shares of $2.25 are 200 and the shares of $2.75 are 700.

To know more about shares here

brainly.com/question/21781662

#SPJ1

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Sienna has $8 and is saving $3 per week. Jacob has $6 and is saving $4 per week. Which model represents the equation that can de
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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
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Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

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13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

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(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

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Men = 6 ; women = 7

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Using calculator :

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(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

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13C7 = 1716

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(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

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Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

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We want to find \displaystyle{  \frac{dy}{dx}, for

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