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Ber [7]
1 year ago
9

An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. If the total cost was $1825.00, how

many shares of each stock did the investor buy? (Round to two decimal places if necessary.)
Mathematics
1 answer:
statuscvo [17]1 year ago
7 0

The shares of $2.25 are 200 and the shares of $2.75 are 700.

According to the question,

We have the following information:

An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. And the total cost was $1825.00.

Now, let's take the shares of $2.25 to be x and the shares of $2.75 to be y.

So, we have the following expression:

x+y = 700

x = 700-y ....(1)

2.25x+2.75y = 1825 ...(2)

Putting the value of x from equation 1:

2.25(700-y)+2.75y = 1825

1575-2.25y+2.75y = 1825

1575+0.5y = 1825

0.5y = 250

y = 250/0.5

y = 500

Now, putting the value of y in equation 1:

x = 700-y

x = 700-500

x = 200

Hence, the shares of $2.25 are 200 and the shares of $2.75 are 700.

To know more about shares here

brainly.com/question/21781662

#SPJ1

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<h2>$26.25</h2>

<em><u>Solving steps:</u></em>

<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>

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<u>p represent amount of moneyt represent totalf represent money found</u>

<h3><em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>

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<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>

add<u> 19.75 from 6.50 </u>

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<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>

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