Sue wrote a doubles fact. It has a sum less than 10 and greater than 4. The addends are each less than 5. What fact might she ha
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<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Yeah Imao you usually do these type of questions on a calculator but I've tried writing it on a calculator and it keeps on saying "error" so I'm gonna guess the question is wrong or sth
but if you type out the question without the bracket before the 12 you'll get 6.63
anyway hope this helps- have a good day bro cya)
