Answer:
0.11069
Step-by-step explanation:
We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.
P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

I hope that works for you!
Answer:
Square base dimension = 15 inches
Maximum volume = 7200 inches^3
Step-by-step explanation:
V = x^2y ..... eq 1
Let the square base be x and the height y
Oversize formular is given by
Y + 4x = 92
Y= 92 - 4x .....eq 2
Put eq 2 into eq 1
V = x^2 ( 92 - 4x^3)
V= 92x^2 - 4x^3
Using derivatives
V= 184x - 12x^2
V'= 0 = 184x - 12x^2
X(184 -12x)
X=0
X = 184/12 = 15.33 approximately 15 inches
Maximum Volume = V= 92(15)^2 -5(15)^3
V= 92(225) - 4(3475)
V= 20700 - 13500
V= 7200 inches^3
Answer:
<h2>5040</h2>
Step-by-step explanation:
<h3>multiply 35 by 144 which will give you your answer (lcm)</h3>
Answer:
x = 14 inches
Step-by-step explanation:
The area of a square piece of paper is 200 square inches.
We need to find the point on the number line below represents the measurement closest to the side length of the piece of wrapping paper. It is shown in the attached figure.
Area of a square = x², x is the side length

or
x = 14 inches
So, the side length of the square is 14 inches. It is shown in point A.
Answer:
y=4/3x
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-0)/(3-0)
m=4/3
y-y1=m(x-x1)
y-0=4/3(x-0)
y=4/3(x)
y=4/3x