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Nostrana [21]
3 years ago
8

What is the product of the 6th square number and the 5th square number?

Mathematics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

900.

Step-by-step explanation:

The first 6 square numbers are 1, 4, 9, 16, 25, 36,

The required product is 25 * 36

= 900.

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If a coin has been altered so that the probability of heads coming up is 3/10, then the probability of tails coming up is also 3
Vadim26 [7]
False. Since the probability of one side of the coin is 3/10, the other must be 7/10.
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Use the graph of the function to find f(-2)
lesya692 [45]

Answer:

Answer D:  f(-2) = 2

Step-by-step explanation:

To evaluate f(-2) we need to find what is the y-value that the graph shows for the x-value "-2".

To find such, we look for the value x = -2 on the horizontal (x) axis (located two units to the left of the origin of coordinates (0,0)), and from there, we investigate at what y-value (value on the vertical y-axis) a line that follows the vertical grid passing through x = -2, intercepts the graph of the function.

That is pictured with a red dot in the attached image. Notice that the y-value at which such intersection occurs is y = 2.

Therefore f(-2) = 2

4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
erastova [34]

Answer:

√8 ==> 2 units, 2 units

√7 ==> √5 units, √2 units

√5 ==> 1 unit, 2 units

3 ==> >2 units, √5 units

Step-by-step explanation:

To determine which pair of legs that matches a hypotenuse length to create a right triangle, recall the Pythagorean theorem, which holds that, for a right angle triangle, the square of the hypotenuse (c²) = the sum of the square of each leg length (a² + b²)

Using c² = a² + b², let's find the hypotenuse length for each given pairs of leg.

=>√5 units, √2 units

c² = (√5)² + (√2)²

c² = 5 + 2 = 7

c = √7

The hypothenuse length that matches √5 units, √2 units is √7

=>√3 units, 4 units

c² = (√3)² + (4)²

c² = 3 + 16 = 19

c = √19

This given pair of legs doesn't match any given hypotenuse length

=>2 units, √5 units

c² = (2)² + (√5)²

c² = 4 + 5 = 9

c = √9 = 3

legs 2 units, and √5 units matche hypotenuse length of 3

=>2 units, 2 units

c² = 2² + 2² = 4 + 4

c² = 8

c = √8

Legs 2 units, and 2 units matche hypotenuse length of √8

=> 1 unit, 2 units

c² = 1² + 2² = 1 + 4

c² = 5

c = √5

Leg lengths, 1 unit and 2 units match the hypotenuse length, √5

3 0
3 years ago
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